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- write a C program to find hcf and lcm
Posted by : thedev27
Friday, October 25, 2013
#include <stdio.h>
long gcd(long, long);
int main() {
  long x, y, hcf, lcm;
  printf("Enter two integers\n");
  scanf("%ld%ld", &x, &y);
  hcf = gcd(x, y);
  lcm = (x*y)/hcf;
  printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);
  printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
  return 0;
}
long gcd(long a, long b) {
  if (b == 0) {
    return a;
  }
  else {
    return gcd(b, a % b);
  }
}
C program to find hcf and lcm using function
#include <stdio.h>
long gcd(long, long);
int main() {
  long x, y, hcf, lcm;
  printf("Enter two integers\n");
  scanf("%ld%ld", &x, &y);
  hcf = gcd(x, y);
  lcm = (x*y)/hcf;
  printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);
  printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
  return 0;
}
long gcd(long x, long y) {
  if (x == 0) {
    return y;
  }
  while (y != 0) {
    if (x > y) {
      x = x - y;
    }
    else {
      y = y - x;
    }
  }
  return x;
}
 
 
 
 
 
 
 
 
